190=2x^2-x

Solution for 190=2x^2-x equation:

190=2x^2-x

We move all terms to the left:

190-(2x^2-x)=0

We get rid of parentheses

-2x^2+x+190=0

a = -2; b = 1; c = +190;
Δ = b2-4ac
Δ = 12-4·(-2)·190
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-39}{2*-2}=\frac{-40}{-4}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+39}{2*-2}=\frac{38}{-4}
=-9+1/2
$